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Which statistical test should your IB Biology IA use? Complete guide to t-test, ANOVA, chi-squared, Pearson, and Spearman with 2025 rubric criteria — what examiners reward and what drops your Data Analysis mark.
Remember these points for your NEET preparation
Your statistical test is worth 1–2 marks on the Data Analysis criterion (6 marks total). Pick the wrong test and your Conclusion will wobble too, because examiners read both criteria together.
This guide walks you through the decision tree from data type → test choice → assumption check, and shows you exactly what the 2025 IB Biology IA rubric rewards.
| Data type | Number of groups | Test |
|---|---|---|
| Continuous (mean comparison) | 2 | t-test (independent or paired) |
| Continuous (mean comparison) | 3+ | One-way ANOVA + Tukey post-hoc |
| Continuous (correlation) | — | Pearson r (linear) or Spearman ρ (rank-based) |
| Categorical counts | — | Chi-squared goodness of fit or independence |
| Non-normal distribution | 2 | Mann-Whitney U |
| Non-normal distribution | 3+ | Kruskal-Wallis |
If you can identify your row in this table, you are already at a 5/6 Data Analysis floor.
Use when you are comparing the means of exactly two groups of continuous data.
IB Biology example: Effect of light vs dark on Elodea photosynthesis rate. You have 10 replicates in light, 10 replicates in dark, and you want to know whether the mean rates differ significantly.
Assumptions to check:
2025 rubric signal: Examiners reward stating the p-value, the 95% confidence interval for the mean difference, and Cohen's d (effect size). A p-value alone caps you at 4/6.
Use when comparing three or more group means. The single biggest error on 2025 IAs is using a t-test on 4 groups — this is mathematically invalid because it inflates your Type I error rate.
IB Biology example: Effect of 5 different enzyme pH levels (3, 5, 7, 9, 11) on amylase activity. You have 5 replicates per pH, 25 data points total.
Assumptions:
2025 rubric signal: If you write "ANOVA showed significant differences (F = 12.3, p < 0.001), and Tukey post-hoc identified pH 7 as significantly higher than all others" — that is 5/6 territory. Adding effect size (η² or ω²) is the 6/6 move.
Use for counts, not means. Two common flavours:
IB Biology example: You observe 78 tasters and 22 non-tasters for PTC in 100 volunteers. Hardy-Weinberg expected under p² + 2pq + q² = 1 predicts different frequencies. Chi-squared goodness of fit tests whether the deviation is significant.
Assumption: Expected count ≥ 5 in each category. If any cell has expected < 5, use Fisher's exact test instead.
2025 rubric signal: Include the chi-squared statistic, degrees of freedom, and p-value. State the null hypothesis explicitly.
Use for two continuous variables where you expect a linear relationship.
IB Biology example: Temperature (continuous) vs enzyme initial reaction rate (continuous). You have one data point per temperature but 5 temperatures.
Assumption: Linear relationship. If you see a curve (e.g. bell-shaped enzyme temperature response), regression with a non-linear model is better.
2025 rubric signal: Report r, r², and the p-value. Explain what r² tells you about the proportion of variance explained.
Use when one or both variables are ordinal, or when the relationship is monotonic but not linear.
IB Biology example: Ranked species abundance across 5 habitats. Use Spearman.
This is the single most common statistical error in IB Biology IAs. It inflates your false positive rate. The fix: one-way ANOVA with Tukey HSD post-hoc.
If you run a t-test on a heavily skewed dataset, the p-value is unreliable. Always check (Shapiro-Wilk on each group, or a Q-Q plot). If non-normal, use the non-parametric equivalent (Mann-Whitney U).
p < 0.05 is not enough. Examiners expect effect size and confidence interval. For ANOVA, report η² (proportion of variance explained). For t-tests, report Cohen's d. For correlations, r² does the same job.
If any cell has an expected count below 5, chi-squared becomes unreliable. Example: you have 100 volunteers split across 8 blood-group categories — several cells will have expected counts of 1-2. Use Fisher's exact test instead.
Examiners flag this. Your test should be justified in Research Design based on the planned experiment, not chosen post-hoc to make your data look significant.
| Criterion | Signal | Mark impact |
|---|---|---|
| Research Design | Justified statistical test before data collection | Unlocks 5/6 |
| Data Analysis | Correct test + assumption checks + effect size | Unlocks 6/6 |
| Conclusion | Quantitative statement using p-value AND effect size | Unlocks 5-6/6 |
| Evaluation | Acknowledging when assumptions were violated and impact on conclusion | Bonus mark |
Research Question: How does temperature (10, 20, 30, 40, 50 °C) affect the initial rate of catalase-mediated O₂ evolution from potato extract?
Data: 5 temperatures × 6 replicates = 30 data points. Initial rates in cm³ s⁻¹.
Test selection rationale (Research Design):
"Because I have five independent groups (temperatures) of continuous data (initial rate), the most appropriate test is one-way ANOVA with Tukey HSD post-hoc to identify which temperature pairs differ. I will verify normality (Shapiro-Wilk at α = 0.05 per group) and homogeneity of variance (Levene's test) before applying the parametric test. If either assumption is violated, I will use Kruskal-Wallis with Dunn's post-hoc instead."
Result reporting (Data Analysis):
"ANOVA showed a significant main effect of temperature on initial rate, F(4, 25) = 42.3, p < 0.001, η² = 0.87 (large effect size). Tukey HSD identified 40 °C as significantly faster than 10, 20, and 50 °C (all p < 0.01). Rate at 40 °C: mean = 2.4 ± 0.18 cm³ s⁻¹ (SE)."
That single paragraph is a 6/6 Data Analysis mark.
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